How do I solve for x: e^x=y-1 It might seem simple but im lost right now.
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Hi xxju1anxx! Originally Posted by xxju1anxx How do I solve for x: e^x=y-1 It might seem simple but im lost right now. I think it is simple, just use the LN: $\displaystyle e^x = y-1$ $\displaystyle LN(e^x) = LN(y-1)$ $\displaystyle x*LN(e) = LN(y-1)$ $\displaystyle x*1 = LN(y-1)$ $\displaystyle x = LN(y-1)$ done. Any questions? Rapha
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