# Solving For X?

• September 24th 2009, 09:43 AM
xxju1anxx
Solving For X?
How do I solve for x:

e^x=y-1

It might seem simple but im lost right now.
• September 24th 2009, 09:51 AM
Rapha
Hi xxju1anxx!

Quote:

Originally Posted by xxju1anxx
How do I solve for x:

e^x=y-1

It might seem simple but im lost right now.

I think it is simple, just use the LN:

$e^x = y-1$

$LN(e^x) = LN(y-1)$

$x*LN(e) = LN(y-1)$

$x*1 = LN(y-1)$

$x = LN(y-1)$

done.

Any questions?

Rapha