Hello,
plz try to solve these question.
Question 1:
Find the limit: $\displaystyle \lim_{x \to 3} \frac{(x-3)}{3x^2-13x+12}$
Factorise the denominator:
$\displaystyle \lim_{x \to 3} \frac{(x-3)}{3x^2-13x+12}=\lim_{x \to 3} \frac{(x-3)}{(x-3)(3x-4)}=\lim_{x \to 3} \frac{1}{3x-4}=1/5$
Question 2:
Determine if the following series converges or diverges:
$\displaystyle \sum_1^{\infty}4^{k-1}$
As an absolute minimum requirement for convergence of a series, the
terms must go to zero as the sumation index goes to infinity. This series
fails this most basic requirement and thus diverges.
RonL