lim (x --> -8) of:

(square root(1-x)) - 3 divided by 2 + (cube root(x))

I believe I should multiply by the congugate, but I'm not getting anywhere.

Thanks for any help

Printable View

- Sep 23rd 2009, 09:32 PMjzelltEvaluating a limit
lim (x --> -8) of:

(square root(1-x)) - 3 divided by 2 + (cube root(x))

I believe I should multiply by the congugate, but I'm not getting anywhere.

Thanks for any help - Sep 23rd 2009, 09:41 PMmr fantastic
I suggest that you first make the substitution $\displaystyle x = t^3$:

$\displaystyle \lim_{t \rightarrow -2} \frac{\sqrt{1 - t^3} - 3}{2 + t}$.

Now multiply numerator and denominator by the conjugate surd, factorise the numerator, divide numerator and denominator by the common factor and then take the limit.