# Finding Vertical Tangent lines

• September 23rd 2009, 03:31 PM
redsox25
Finding Vertical Tangent lines
I need to find the vertical tangents for this function
$2y^3+y^3-y^5=x^4-2x^3+x^2$
I got this for the derivative
$dy/dx=(4X^3-6x^2+2x)/(6y^2+2y-5y^4)$
I know to set the denominator equal to zero and from there I'm stuck

• September 23rd 2009, 03:38 PM
skeeter
Quote:

Originally Posted by redsox25
I need to find the vertical tangents for this function

$2y^3+y^3-y^5=x^4-2x^3+x^2$ check the exponents on the left side, please

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• September 23rd 2009, 03:41 PM
redsox25
oops sorry about that
$2y^3+y^2-y^5=x^4-2x^3+x^2$
• September 23rd 2009, 04:08 PM
skeeter
other than y = 0 , the other three zeros look to be irrational when graphed w/ a calculator. unless there's some clever trick, solving by hand may be rather messy.

http://www.math.vanderbilt.edu/~schectex/courses/cubic/