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Math Help - 1/((x^2)(x + 7)) = INFINITY

  1. #1
    s3a
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    1/((x^2)(x + 7)) = INFINITY

    lim x-->0 1/((x^2)(x + 7)) = INFINITY

    but my question is:
    if it says x-->0 instead of x-->0+ or x-->0-, so how do you know that both x-->0+ AND x-->0- go to a infinite y value?

    Any help would be greatly appreciated!
    Thanks in advance!
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  2. #2
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    take the limit of f(x) both as x->0- and from the right.
    If they both equal possitive infinity then:
    lim f(x) as x-> 0 is infinity.
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  3. #3
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    Quote Originally Posted by s3a View Post
    lim x-->0 1/((x^2)(x + 7)) = INFINITY

    but my question is:
    if it says x-->0 instead of x-->0+ or x-->0-, so how do you know that both x-->0+ AND x-->0- go to a infinite y value
    In either case x^2 is positive and near 0 while x+7 is near 7.
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