At all points on a certan curve, y'' = 2x. The point (3,6) belongs to the curve and its tangent at this point is inclined at 45 degrees to the X-axis. Find the equation of the curve.
How exactly do I use the bold part for this problem? I've found y' = x^2 + c...
Oh, and is the answer actually y = x^2 - 5x + 12 (txtbk answer) cause it doesn't look right to me.