# Thread: quick vector calc question

1. ## quick vector calc question

how would i go about graphing
f(x,y,z)= -1
or any constant for that matter...?

2. you can't.

for functions of the form w = f(x,y,z) it takes three dimensions for the domain and would require a 4th dimension for the range which humans can't do.

One way of thinking of this is think of f(x,y,z) as the temperature at any point in 3 space. In your case the temp is -1 everywhere.

You can't visualuze temperature in your 3 -D world can you human?

Actually you can if you add color as with infrared imaging

3. i was thinking it seemed impossible. i'm studying for my first test which is in 20 minutes. i was just wondering thanks for reassuring me

4. ## Elaboration level surfaces

if for example f(x,y,z) = x^2 + y^2 +z^2

then f(x,y,z) = 1 woulde be the level surface

x^2 + y^2 +z^2 = 1

meaning that on a sphere of radius 1 f has the same value at all points.

This is analagous to the level curve for fns of 2 variables

5. thanks! one last quick question..the formula for an elipse. is it x^2/a + y^2/b =1

6. yes --if it is centered at the origin