How can i solve this limit without using L'hospital's rule? Limit[(2 - Sqrt[x + 1])/(x - 3), x -> 3]
Follow Math Help Forum on Facebook and Google+
multiply top and bottom by sqrt(x+1) you should get -(x-3)/[(x-3)sqrt(x+1)]
Originally Posted by Calculus26 multiply top and bottom by sqrt(x+1) you should get -(x-3)/[(x-3)sqrt(x+1)] Don't u mean top and bottom by 2 + sqrt(x+1). And the problem is that after I solve that I get: -(x-3)/[(x-3)(2 + sqrt(x+1)] And when the limit is taken, it gives 0
yes multiply top and bottom by 2 +sqrt(x+1) then you get -1/[2+sqrt(x+1)] and lim -1/[2+sqrt(x+1)] = -1/3 not 0 x->0
Oh, I see where my error was, how embarrasing. Thanks so much
View Tag Cloud