Can someone with a 3D graphing program show me what the graph of these two equations looks like. Thanks in advance. $\displaystyle z=f(x,y)=1-x^2-y^2$ $\displaystyle z=f(x,y)={\sqrt(1-x^2-y^2)}$
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Originally Posted by Infernorage Can someone with a 3D graphing program show me what the graph of these two equations looks like. Thanks in advance. $\displaystyle z=f(x,y)=1-x^2-y^2$ $\displaystyle z=f(x,y)={\sqrt(1-x^2-y^2)}$ Here you go. They're pretty close together so it might be tough to tell them apart.
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