Thread: What do i do from here

USe taylor approx to avoid loss of sig.

(e^x - 1) /x

= ((1 + x + x^2/2! + x^3/3!) - 1) /x

= (x + x^2/2! + x^3/3!) / x

= 1 + x/2! + x^2/3!

Now what?

Originally Posted by jzellt

USe taylor approx to avoid loss of sig.

(e^x - 1) /x

= ((1 + x + x^2/2! + x^3/3!) - 1) /x

= (x + x^2/2! + x^3/3!) / x

= 1 + x/2! + x^2/3!

Now what?

That's pretty much all you need to do, since you've avoided loss of significance at x=0! (originally, if you evaluated the function at x=0, you got the indeterminate case 0/0. Now, if you evaluate the function at x=0, you get 1).