Results 1 to 2 of 2

Math Help - Ieee

  1. #1
    Super Member
    Joined
    Feb 2008
    Posts
    535

    Ieee

    I'm asked to find the binary double precision IEEE floating point expression.

    My professor did this for the number 1,000

    He said 1000 = 1111101000
    = +1 x 1.11101 x 2^9

    And thats the answer but i don't understand how to get the 1.11101 and the 2^9.

    Any advice? Thanks.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Rhymes with Orange Chris L T521's Avatar
    Joined
    May 2008
    From
    Chicago, IL
    Posts
    2,844
    Thanks
    3
    Quote Originally Posted by jzellt View Post
    I'm asked to find the binary double precision IEEE floating point expression.

    My professor did this for the number 1,000

    He said 1000 = 1111101000
    = +1 x 1.11101 x 2^9

    And thats the answer but i don't understand how to get the 1.11101 and the 2^9.

    Any advice? Thanks.
    Floating point is in the form 1.(something)

    Since we have 1111101000_2, we want to rewrite it in the floating point form: 1.(something).

    We note that in "scientific notation" (I use that very loosely), 1111101000._2=1.111101000\times (10_2)^9=1.111101\times 2^9

    So your professor is correct in saying 1000_{10}=1111101000_2=+1\times1.111101\times 2^9

    Does this clarify things?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. IEEE 754 Single Precision Floating Point System:
    Posted in the Advanced Math Topics Forum
    Replies: 2
    Last Post: September 26th 2010, 03:22 AM
  2. IEEE floating point arithmetic
    Posted in the Math Software Forum
    Replies: 1
    Last Post: March 13th 2009, 02:18 PM

Search Tags


/mathhelpforum @mathhelpforum