# Math Help - Ieee

1. ## Ieee

I'm asked to find the binary double precision IEEE floating point expression.

My professor did this for the number 1,000

He said 1000 = 1111101000
= +1 x 1.11101 x 2^9

And thats the answer but i don't understand how to get the 1.11101 and the 2^9.

2. Originally Posted by jzellt
I'm asked to find the binary double precision IEEE floating point expression.

My professor did this for the number 1,000

He said 1000 = 1111101000
= +1 x 1.11101 x 2^9

And thats the answer but i don't understand how to get the 1.11101 and the 2^9.

Since we have $1111101000_2$, we want to rewrite it in the floating point form: $1.(something)$.
We note that in "scientific notation" (I use that very loosely), $1111101000._2=1.111101000\times (10_2)^9=1.111101\times 2^9$
So your professor is correct in saying $1000_{10}=1111101000_2=+1\times1.111101\times 2^9$