Hi,

I am trying to figure out this question but I really can't understand it. Can someone please work through it and explain in a simple way what the steps are?

A particle is moving on a straight line path with acceleration given by dv/dt=-2e^-x where x is the distance of the particle from the origin and v is the velocity of the particle.

Knowing that d/dx(v^2/2)=dv/dt,hence determine that if v=2 when x=0 then v=2e^-(x/2)

Thanks

David