curve sketching clarification
My equation is f(x)=x/x^2-4
So from that, heres what I have gotten so far...
-domain: X is a real number that cannot be 2, -2
- x-intercept is 0
- y intercept is 0
-There is a horizontal asymptote at y=0
-There are vertical asymptotes at x=2 and x=-2
-To find the critical numbers, I have to take the derivative and I did so using the quotient rule and came up with
1) How do I find the critical numbers by setting the function equal to 0? Am i dealing with the numerator? denominator?