Thread: help with question

1. help with question

Can someone please show me a walk through for

$\displaystyle d/dx (arcsin((2x^2+3)/5)))$

2. Hi psupernak

Originally Posted by psupernak
Can someone please show me a walk through for

$\displaystyle d/dx (arcsin((2x^2+3)/5)))$
Is is $\displaystyle [arcsin(x)] ' = \frac{1}{\sqrt{1-x^2}}$

and [(2x^2+3)/5]' = 4/5*x

Now use the chain rule

$\displaystyle d/dx (arcsin((2x^2+3)/5))) = 4/5*x*\frac{1}{\sqrt{1-((2x^2+3)/5)^2}}$

regards
Rapha