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Thread: help with question

  1. #1
    Junior Member
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    Nov 2008
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    help with question

    Can someone please show me a walk through for

    $\displaystyle d/dx (arcsin((2x^2+3)/5)))$
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  2. #2
    Senior Member
    Joined
    Nov 2008
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    Hi psupernak

    Quote Originally Posted by psupernak View Post
    Can someone please show me a walk through for

    $\displaystyle d/dx (arcsin((2x^2+3)/5)))$
    Is is $\displaystyle [arcsin(x)] ' = \frac{1}{\sqrt{1-x^2}}$

    and [(2x^2+3)/5]' = 4/5*x

    Now use the chain rule

    $\displaystyle d/dx (arcsin((2x^2+3)/5))) = 4/5*x*\frac{1}{\sqrt{1-((2x^2+3)/5)^2}}$

    regards
    Rapha
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