1. ## Calculus Simplification Question

I can't seem to simplify these expressions:

as seen below:

In the form of f(c)/g(c)

In the form of f(x)/g(x)

in the form of A/B

2. Originally Posted by frozenflames
I can't seem to simplify these expressions:

as seen below:

Multiply the first by $\displaystyle \frac{(c-6)}{(c-6)}$ and see where that takes you.

Seeing this, you should be able to do the second.

3. already tried and i got (6c-34)/(-6c+36) which doesn't make any sense..

4. Originally Posted by frozenflames
already tried and i got (6c-34)/(-6c+36) which doesn't make any sense..
$\displaystyle \frac{(1+\frac{6}{c-6})}{(1-\frac{6}{c-6})}\frac{(c-6)}{(c-6)}$$\displaystyle =\frac{(c-6)+6}{(c-6)-6}$ ...

5. that makes sense! i was doing it completely wrong! okay thanks, i'll figure out the other two by myself..appreciate it!

6. Originally Posted by frozenflames
that makes sense! i was doing it completely wrong! okay thanks, i'll figure out the other two by myself..appreciate it!

7. got the second one, now im stuck on the third..

8. Originally Posted by frozenflames
got the second one, now im stuck on the third..
It would help if you rewrote it like this...

$\displaystyle \left(\frac{2}{a+h}-\frac{2}{a}\right)\left(\frac{1}{h}\right)$

Find a LCD in the first factor and see what happens.

9. I get this:

(-2h^2)(a^2+ah)

but it has to be in the form of A/B which is very confusing...

10. Originally Posted by frozenflames
I get this:

(-2h^2)(a^2+ah)

but it has to be in the form of A/B which is very confusing...
Find the LCD

$\displaystyle \left[\frac{2a-2(a+h)}{a(a+h)}\right]\frac{1}{h}$

Now try. Look at what happens when the numerator implifies. Do you see any cross cancelleng in the future?

11. would that be ah(a+h)?

12. Originally Posted by frozenflames
would that be ah(a+h)?
Yeah, that's the denominator. So.....Simplify the rest.

I don't want you to take this the wrong way, But... You need to get this stuff and get it quick because if you are in calc 1, this type of stuff is going to hurt your performance. This type of simplification is done in algebra 1. You have your work cut out for you. And don't get me wrong, I'll help you. But, just know that you are going to have to step it up.

13. i totally get what you mean, it has been 3 years since i last took calculus and have to take one more course to fulfill my requirements so it's just taking a while to get things refreshed. very sorry to bother you, but it just takes a while for things like this to get back in memory as my major is no where related to calculus.

i am still flustered on this problem.

(I got 2ah^2-2ah-2h^2) (a^2+ah)