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**asweet1** Using the conjecture that d/dx*x^n=nx^n-1 for positive integer values of n. In this problem we look at negative values of n instead.

Let f(x)= x^-1.

(a) write the difference quotient for f(x).

(b) Let the change of x= .01. Use the table command on your calculator to build a table of values for the difference quotient.

-Compare the values in your table to the values of -1*x^-2. Can you guess what f'(x) might be based on your table of values?

__x diff quotient -1*x^(-2)__

-4

-2

-1

-1/2

-1/3

I am not sure how to go about this problem is the difference quotient for part a d/dx*x^-1=nx^-1-1?

If someone can help me understand the quotient I am suppose to use and ow i Use it in part b I think I can figure out the table on my own.