difference quotient ...Using the conjecture that d/dx*x^n=nx^n-1 for positive integer values of n. In this problem we look at negative values of n instead.
Let f(x)= x^-1.
(a) write the difference quotient for f(x).
(b) Let the change of x= .01. Use the table command on your calculator to build a table of values for the difference quotient.
-Compare the values in your table to the values of -1*x^-2. Can you guess what f'(x) might be based on your table of values?
x diff quotient -1*x^(-2)
I am not sure how to go about this problem is the difference quotient for part a d/dx*x^-1=nx^-1-1?
If someone can help me understand the quotient I am suppose to use and ow i Use it in part b I think I can figure out the table on my own.