Thread: derivative problem

Hello I'm trying to figure out how to do this problem

$\displaystyle d\frac{3}{\sqrt{t^2-4t}}$

Do I use the quotient rule and then chain rule when deriving the denominator?

Originally Posted by LovesMeTrike

Hello I'm trying to figure out how to do this problem

$\displaystyle d\frac{3}{\sqrt{t^2-4t}}$

Do I use the quotient rule and then chain rule when deriving the denominator?

What is d? Does it just mean derivative?

If so, then use the chain rule, yes.

Write it as $\displaystyle 3 (t^2-4t)^{\frac{-1}{2}}$ and use chain rule.

ok I got to $\displaystyle 3(\frac{-1}{2})(t^2 - 4t)^{1/2}(2t-4)$

The answer to the problem is $\displaystyle \frac{-3(2t-4)}{2\sqrt{t^2 - 4t}^3}$

Where did I go wrong?

Yes the d just meant derivative