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Math Help - finding equation of tangent plane

  1. #1
    Senior Member
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    finding equation of tangent plane

    z=x^2+y^2 at point (3,4,5)
    I've taken the partial derivatives and plugged in the value for x and y. I'm not sure what to do next.

    So fx=2x and fy=2y
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  2. #2
    MHF Contributor Calculus26's Avatar
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    The normal is

    N = -fx i -fy j + k evaulated at (3,4,5)

    N = -6 i - 8 j + k

    If the normal to a plane is ai+bj+ck then then the eqn is

    a(x-x0)+b(y-y0) +z -z0 = 0


    -6(x-3) -8(y-4) + z - 5 = 0

    Solve for z
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