$\displaystyle z=x^2+y^2$ at point (3,4,5) I've taken the partial derivatives and plugged in the value for x and y. I'm not sure what to do next. So $\displaystyle fx=2x$ and $\displaystyle fy=2y$
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The normal is N = -fx i -fy j + k evaulated at (3,4,5) N = -6 i - 8 j + k If the normal to a plane is ai+bj+ck then then the eqn is a(x-x0)+b(y-y0) +z -z0 = 0 -6(x-3) -8(y-4) + z - 5 = 0 Solve for z
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