I have to integrate
I'm getting
37((1/4(cos(2x)))-(log(cos(x))))
It is wrong though. Any help is appreciated.
Thanks,
Jay
You forgot parentheses or didn't know how to write this is Latex. It should be $\displaystyle 37\int\frac{\sin^3{x}}{\cos{x}}dx$. Easy error to make.
Yes it would! Have you used u-substitution before? You should have if you are assigned this problem. Let u = cos(x) and rewrite the integral.