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Math Help - Calc 2 Integration

  1. #1
    Junior Member
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    Calc 2 Integration

    I have to integrate



    I'm getting
    37((1/4(cos(2x)))-(log(cos(x))))

    It is wrong though. Any help is appreciated.

    Thanks,
    Jay
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  2. #2
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    the tan becomes sin/cos and that cancells off the adjacent (cos{x})^2. Then take out the 37 so now you've got 37\int\frac{\sin{x}^3}{\cos{x}}dx
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  3. #3
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    still getting the same answer. It says to use ln(abs(u)) where appropriate
    Would that make any difference?
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  4. #4
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    Quote Originally Posted by superdude View Post
    the tan becomes sin/cos and that cancells off the adjacent (cos{x})^2. Then take out the 37 so now you've got 37\int\frac{\sin{x}^3}{\cos{x}}dx
    You forgot parentheses or didn't know how to write this is Latex. It should be 37\int\frac{\sin^3{x}}{\cos{x}}dx. Easy error to make.

    Quote Originally Posted by Hellacious D View Post
    still getting the same answer. It says to use ln(abs(u)) where appropriate
    Would that make any difference?
    Yes it would! Have you used u-substitution before? You should have if you are assigned this problem. Let u = cos(x) and rewrite the integral.
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