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Math Help - Help deriving an equation

  1. #1
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    Nov 2007
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    Help deriving an equation

    I need to derive this function:

    \frac{2a}{1-x^2-a^2}

    a is a constant

    This is how i tried to solve it:

    2a(1-x^2-a^2)^{-1}

    \frac{4ax}{(1-x^2-a^2)^2}

    Is that the right answer?

    Thanks
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  2. #2
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    Quote Originally Posted by sebasto View Post
    I need to derive this function:

    \frac{2a}{1-x^2-a^2}

    a is a constant

    This is how i tried to solve it:

    2a(1-x^2-a^2)^{-1}

    \frac{4ax}{(1-x^2-a^2)^2}

    Is that the right answer?

    Thanks
    I think what you mean is you want to DIFFERENTIATE (not derive) that EXPRESSION (not function!)

    Remember is: If  y(x) = \frac{u(x)}{v(x)} , then  y'(x) = \frac{v(x) u'(x) - u(x) v'(x)}{(v(x))^2}
    Last edited by Mush; September 17th 2009 at 02:57 PM.
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  3. #3
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    Well, it was a function from the beginning, but I just omitted the f(x) and f'(x)

    Here we go again then..

    I need to derive this function in relation to x:

    f(x)=\frac{2a}{1-x^2-a^2}

    a is a constant

    This is how i tried to solve it:

    f(x)=2a(1-x^2-a^2)^{-1}

    f'(x)=\frac{4ax}{(1-x^2-a^2)^2}

    Is that the right answer?
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  4. #4
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    Dec 2008
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    Scotland
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    Quote Originally Posted by sebasto View Post
    Well, it was a function from the beginning, but I just omitted the f(x) and f'(x)

    Here we go again then..

    I need to derive this function in relation to x:

    f(x)=\frac{2a}{1-x^2-a^2}

    a is a constant

    This is how i tried to solve it:

    f(x)=2a(1-x^2-a^2)^{-1}

    f'(x)=\frac{4ax}{(1-x^2-a^2)^2}

    Is that the right answer?
    Again, you want to differentiate this function with respect to x.

    I think you're right.
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