find derivative with respect to y.holding x constant. Is that right or did i do that wrong? Or is is suppose to be ???? Suggestions?
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The point here is "holding x constant". So treat it as though it were: or even: ... which should be an elementary application of chain rule.
Originally Posted by el123 find derivative with respect to y.holding x constant. Why is there an equal sign here? Originally Posted by el123 Is that right or did i do that wrong? Or is is suppose to be ???? Suggestions? Is that supposed to be the partial y for your very first expression? because if you consider y as the only variable it's just power rule.
Originally Posted by Matt Westwood The point here is "holding x constant". So treat it as though it were: or even: ... which should be an elementary application of chain rule. In fact, in the last bit of your post I see you've done it right.
not meant to be equal , meant to be minus lol
Originally Posted by Matt Westwood In fact, in the last bit of your post I see you've done it right. oh hmm you're right I didn't notice that either . . . That is right.
so i got it right in the second equation?
Originally Posted by el123 so i got it right in the second equation? Yes - good job. Partial differentiation, it's more simple than you'd initially suspect.
if: then: That solution for the partial y is correct.
gracias amigos!
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