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Math Help - How would i work this problem out

  1. #1
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    How would i work this problem out

    we have the function f(x)=2x^3-3x^2-12x+20
    first we have to find the zeroes. we cant use a calculator on this problem so i was thinking about using the anti derivative or something but you would need a point. any ideas?

    also we need to write an equation for the line normal to the graph of f at x=0. I know the first step is to take the derivative of the equation and plug in the 0 but i forget if that solves for the tangent or normal slope.

    lastly we need to find the x and y coordinates of all the points on the graph of f where the line tangent to the graph is parallel to the x-axis. Im not sure how to aproach that at all.
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  2. #2
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    Quote Originally Posted by calc_help123 View Post
    we have the function f(x)=2x^3-3x^2-12x+20
    first we have to find the zeroes. we cant use a calculator on this problem so i was thinking about using the anti derivative or something but you would need a point. any ideas?

    also we need to write an equation for the line normal to the graph of f at x=0. I know the first step is to take the derivative of the equation and plug in the 0 but i forget if that solves for the tangent or normal slope.

    lastly we need to find the x and y coordinates of all the points on the graph of f where the line tangent to the graph is parallel to the x-axis. Im not sure how to aproach that at all.
    Solving f(x)=2x^3-3x^2-12x+20 = 0 has nothing to do with the anti-derivative. Start by noting that f(2) = 0.
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