Find all numbers c that satisfy the conclusion of the mean value theorem.

$\displaystyle f(x)=3x^2+2x+5, [-1,1]$

this is what i get

$\displaystyle f'(c)=\frac{f(b)-f(a)}{b-a}$

a=-1

b=1

so

$\displaystyle f'(c)=\frac{f(1)-f(-1)}{1-(-1)}$

= 2

never mind i figured it out

well tell me if this is correct

f'(c)=6c+2

6c+2=2

c=0