Good evening everyone need some help with this problem i got wrong, have an exam tomorrow and i'm trying to figure this out. Thanks in advance!
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Originally Posted by tecknics Good evening everyone need some help with this problem i got wrong, have an exam tomorrow and i'm trying to figure this out. Thanks in advance! $\displaystyle \lim_{x \to -5^-} f(x) = \lim_{x \to -5^+} f(x) = -12$ and $\displaystyle \lim_{x \to 1^-} f(x) = \lim_{x \to 1^+} f(x) = 12$ you'll get two equations in terms of $\displaystyle a$ and $\displaystyle b$ ... solve the system.
Last edited by skeeter; Sep 16th 2009 at 02:20 PM. Reason: fix x-values in 2nd limit
Originally Posted by skeeter $\displaystyle \lim_{x \to -5^-} f(x) = \lim_{x \to -5^+} f(x) = -12$ and $\displaystyle \lim_{x \to -5^-} f(x) = \lim_{x \to -5^+} f(x) = 12$ you'll get two equations in terms of $\displaystyle a$ and $\displaystyle b$ ... solve the system. I know how to do that part you just showed, but as far as the next step im lost
$\displaystyle \lim_{x \to -5^-} -12 = \lim_{x \to -5^+} ax+b$ $\displaystyle -12 = a(-5)+b$ $\displaystyle \lim_{x \to 1^-} ax+b = \lim_{x \to 1^+} 12$ $\displaystyle a+b = 12$ solve the system
Originally Posted by skeeter $\displaystyle \lim_{x \to -5^-} -12 = \lim_{x \to -5^+} ax+b$ $\displaystyle -12 = a(-5)+b$ $\displaystyle \lim_{x \to 1^-} ax+b = \lim_{x \to 1^+} 12$ $\displaystyle a+b = 12$ solve the system That makes sense to me now, but now i'm lost for solving the system, i was in Iraq for a year and completely forgot about everything math related and need to practice some more.
Wooo, i got it just now thank you very much!
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