Thread: [SOLVED] How to evaluate this integral

Hi,
I would like some help evaluating this indefinite integral

∫ [x^2 sqrt(9x+5)] dx

Im not sure how to go about solving this

thanks!

$\displaystyle \sqrt{9x+5}=u\Rightarrow x=\frac{u^2-5}{9}\Rightarrow dx=\frac{2}{9}udu$

$\displaystyle \frac{2}{729}\int(u^2-5)^2u^2du=\frac{2}{729}\int(u^6-10u^4+25u^2)du$

Can you continue?

ahh I understand, thank-you for replying .
Yes I can continue