Hi, I would like some help evaluating this indefinite integral ∫ [x^2 sqrt(9x+5)] dx Im not sure how to go about solving this thanks!
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$\displaystyle \sqrt{9x+5}=u\Rightarrow x=\frac{u^2-5}{9}\Rightarrow dx=\frac{2}{9}udu$ $\displaystyle \frac{2}{729}\int(u^2-5)^2u^2du=\frac{2}{729}\int(u^6-10u^4+25u^2)du$ Can you continue?
ahh I understand, thank-you for replying . Yes I can continue
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