find a curve thru the origin whose length from x=0 to x=1 is:
L= ∫ √ 1+ 1/4 e^x dx (all under the square root)
L= ∫ ( 1+ 1/4 e^x)^1/2 dx
L= [2/3 (1+ 1/4 e^x)^3/2 (x + 1/4e^x)]
but i don't know what to do next...
the answer is : y= e^x/2 -1
find a curve thru the origin whose length from x=0 to x=1 is:
L= ∫ √ 1+ 1/4 e^x dx (all under the square root)
L= ∫ ( 1+ 1/4 e^x)^1/2 dx
L= [2/3 (1+ 1/4 e^x)^3/2 (x + 1/4e^x)]
but i don't know what to do next...
the answer is : y= e^x/2 -1