Thread: antiderivative of (1 e^tanx) sec^2 x dx

∫ (from 0 to pi/4) (1 e^tanx) sec^2 x dx

i thought to use u subsitution:
u=tanx
du=secx dx
so that:
∫ (from 0 to pi/4)(1+e^u) du
but then i'm confused

when doing a substitution, you need to change the bounds, besides you're on the right track, so now split that sum into two integrals, which you should know how to solve since they're immediate.

Originally Posted by Krizalid

when doing a substitution, you need to change the bounds, besides you're on the right track, so now split that sum into two integrals, which you should know how to solve since they're immediate.

how do i split the sum into two integrals?