∫(from 0 to pi/4) (1 e^tanx) sec^2 x dx

i thought to use u subsitution:

u=tanx

du=secx dx

so that:

∫(from 0 to pi/4)(1+e^u) du

but then i'm confused

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- September 15th 2009, 07:42 PMgenlovesmusic09antiderivative of (1 e^tanx) sec^2 x dx
**∫**(from 0 to pi/4) (1 e^tanx) sec^2 x dx

i thought to use u subsitution:

u=tanx

du=secx dx

so that:

**∫**(from 0 to pi/4)(1+e^u) du

but then i'm confused - September 15th 2009, 07:54 PMKrizalid
when doing a substitution, you need to change the bounds, besides you're on the right track, so now split that sum into two integrals, which you should know how to solve since they're immediate.

- September 15th 2009, 08:03 PMgenlovesmusic09