Use the intermediate value theorem to show that the equation $\displaystyle -x^4 + 3x^3 - 2x^2 + 3x - 5 = 0$ has at least two real solutions.
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f(1) = -2 f(2) = 1 f(3) = -14 Therefore there is a zero between 1 and 2 and one between 2 and 3
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