Use the intermediate value theorem to show that the equation $\displaystyle -x^4 + 3x^3 - 2x^2 + 3x - 5 = 0$ has at least two real solutions.

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- Sep 15th 2009, 05:34 PMxxlvhIntermediate Value Thereom
Use the intermediate value theorem to show that the equation $\displaystyle -x^4 + 3x^3 - 2x^2 + 3x - 5 = 0$ has at least two real solutions.

- Sep 15th 2009, 05:52 PMCalculus26
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f(1) = -2

f(2) = 1

f(3) = -14

Therefore there is a zero between 1 and 2 and one between 2 and 3