any to help me with this problem!!! find the nth term of the series 1,2,4,7,11 thanks for your answers in advance
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The difference in each consecutive term is increasing by 1. $\displaystyle 1,2,4,7,11,\dots$ $\displaystyle 1(+1)=2$ $\displaystyle 2(+2)=4$ $\displaystyle 2(+3)=7$ and so on
Originally Posted by khotso any to help me with this problem!!! find the nth term of the series 1,2,4,7,11 thanks for your answers in advance 00+01 = 01 = a(00) 01+01 = 02 = a(01) 02+02 = 04 = a(02) 03+04 = 07 = a(03) 04+07 = 11 = a(04) 05+11 = 16 = a(05) 06+16 = 22 = a(06) 07+22 = 29 = a(07) 08+29 = 37 = a(08) 09+37 = 46 = a(09) 10+46 = 56 = a(10) a(n) = a(n-1) + n Is this what you were looking for?
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yes that is the answer
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