Hi, I'm confused on how to figure out the problem$\displaystyle \lim_{x \to 27} \frac{x-27}{x^\frac{1}{3}-3}$. I have the problem worked out, but I am having difficulty understanding how to get from step one to step 2:

$\displaystyle \lim_{x \to 27} \frac {(x^\frac{1}{3})^3-(3)^3}{x^\frac{1}{3}-3}$

to

$\displaystyle \lim_{x \to 27}\frac {(x^\frac{1}{3}-3)(x^\frac{2}{3}+3x^\frac{1}{3}+9)}{(x^\frac{1}{3}-3)}$

Thanks for the help in advance.