EDIT: Let me rephrase the topic, PLOT of r = 4sin(theta)
Hi, I'm not sure if this is the right section, but here's my problem.
I'm having trouble understanding why the graph (in polar coordinates) of r = 4sin(theta) is just a circle split by the y-axis ontop of the x-axis with a diameter of 4.
My intuition tells me that the circle should be reflected on the x-axis, leaving a figure-8 shape, but every program I've graphed it in to verify tells me that it's simply the upper circle.
Why would the domain of theta be restricted to 0-pi.
The context of the question is a problem (which I've solved):
Find the surface area of r*cos(3*theta) above the domain r = rsin(theta).