Hi all, looking for the long answer to: $\displaystyle \int ye^{-y(1+x)} dy$ from 0 to 1 thanks! if im asked $\displaystyle \int ye^{-y(1+x)} dx$ would there be a difference?
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integrate by parts treating x as a constant--your answer will still have x in it if im asked would there be a difference? yes -- here you treat y as a constant and it would be easier the Ad would be simply -e^[-y(1+x)]
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