in previous attachment the integrand shouldn't be squared
see correct attachment
I know how to use the formula (sqrt(1 + dy^2)dx), but I have no idea how to integrate this. After taking the derivative of the given equation I getFind the length of the curve y=(x^6+8)/(16x^2) from x=2 to x=3.
dy=(x^4/16-1/x^3). I don't know what to do once I square it...