find the values of x that give relative extrema for the function f(x)= (x+1)^2(x-2).
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Originally Posted by gracy find the values of x that give relative extrema for the function f(x)= (x+1)^2(x-2). Absolute or local extrema? I'll assume absolute. f'(x) = 3*(x - 1)*(x + 1) 0 = 3*(x - 1)*(x + 1) x = -1, 1 (-inf, -1) + (-1, 1) - (1, inf) + Thus, we have a relative maximum at x = -1, and a relative minimum at x = 1.
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