guys please help me with this problem: Find a unit vector perpendicular to plane PQR determined by the points P(3,-3,-1), Q(2,1,-1), and R(2,-2,-1) the book says the answer is : (+-)(2/3i +2/3j+1/3K)
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Let u be the vector from P to Q and v be the vector from Q to R Then N = u x v the unit normal is (u x v)/|u x v|
i tried that way but still getting different answer than the book
Check the coordinates of the given points but with the pts you gave: u = -i + 4 j (P to Q) v = -3 j ( Q to R) u x v = k
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