guys please help me with this problem, i am sooo confused
Find the intersection:
x+y+z=-1( negative 1)
x+y=5
The book says the answer is X=-t
Y=5+t
Z=-6
i dont know how!!
1)x+y+z=-1
2) x+y=5
The intersection of 2 planes is a line
subtract 1) - 2) to get z = -6
This leaves (if you plug in z = - 6)
1)x+y= 5
2) x+y=5
Which is true for all real numbers
Let x = t then y = 5 - t
So the parametric equations of the line is x= t y = 5- t z = -6