# first calculus assignment of the year

• Sep 13th 2009, 12:47 PM
OCD
first calculus assignment of the year
Hi, first post here. Also first calculus assignment; it's called preparation for calculus so I feel like it's supposed to be easy, and I feel a bit of shame that I'm asking for help, but here goes.

1. Find the intercepts (if any).
\$\displaystyle y=(x-1)/(x-2)\$

2. Check for symmetry with respect to both axes and to the origin. Show work.
\$\displaystyle x^2y-x^2+4y=0\$

I hope this is in the right place (it may really be more of pre-calculus work) and thanks!
• Sep 13th 2009, 01:15 PM
VonNemo19
Quote:

Originally Posted by OCD
Hi, first post here. Also first calculus assignment; it's called preparation for calculus so I feel like it's supposed to be easy, and I feel a bit of shame that I'm asking for help, but here goes.

1. Find the intercepts (if any).
\$\displaystyle y=(x-1)/(x-2)\$

2. Check for symmetry with respect to both axes and to the origin. Show work.
\$\displaystyle x^2y-x^2+4y=0\$

I hope this is in the right place (it may really be more of pre-calculus work) and thanks!

1. when y is zero, what is x? Conversly, when x is zero, what is y?

2. Begin by solving for y.

a)if your insert any -x and x which both yield a positive y, then there is symetry about y.

b)If x gives y, and -x gives -y, thenthere is symetry about the origin.

c) assuming that y is not a function, then if x gives two values of y (+/-y), then there is symetry about the x axis.
• Sep 13th 2009, 01:30 PM
OCD
thanks! I think I've got 1 now.

The problem with # two is splitting up the x and the y at the beginning. That's where I keep getting stuck because I subtract \$\displaystyle -x^2 \$ from the left side and then try to divide the other \$\displaystyle x^2\$ to separate it from the y, but I know this isn't right.