OK, f(x)=(3x^2 + 13x + 12)/(x^2 + x - 6)
This is what I got from that:
factored form f(x) = (3x + 4)/(x-2)
y-intercept: y = -2
x-intercept(s): x = -4/3
horizontal asymptote: y = 3
vertical asymptote: x = 2
removable discontinuity at x = 2
Now i have to find the limit of f(x) as x approaches the removable discontinuity. If I use 2, I get undefined.
Am I doing something wrong??
1. at x=2
2. at x=-3
But if we factor...
I removed one of the discontinuities.
So, it is now possible to know because it is equal to the
So, now by direct substitution
Does this make sense?