OK, f(x)=(3x^2 + 13x + 12)/(x^2 + x - 6)

This is what I got from that:

factored form f(x) = (3x + 4)/(x-2)

y-intercept: y = -2

x-intercept(s): x = -4/3

horizontal asymptote: y = 3

vertical asymptote: x = 2

removable discontinuity at x = 2

Now i have to find the limit of f(x) as x approaches the removable discontinuity. If I use 2, I get undefined.

Am I doing something wrong??