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Thread: Trig Limits

  1. September 13th 2009, 10:01 AM #1
    discobob
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    Trig Limits

    i'm having trouble with this limit. Can you guys help?

    \lim_{x\to 0} \frac{x(1-\cos(x))}{\sin^2 x}

    Also, i cant use L'Hopital's rule
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  2. September 13th 2009, 10:14 AM #2
    stapel
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    sin^2(x) = 1 - cos^2(x) = [1 - cos(x)][1 + cos(x)]

    Then cancel....

    Does that help?
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