# Trig Limits

• September 13th 2009, 10:01 AM
discobob
Trig Limits
i'm having trouble with this limit. Can you guys help?

$\lim_{x\to 0} \frac{x(1-\cos(x))}{\sin^2 x}$

Also, i cant use L'Hopital's rule
• September 13th 2009, 10:14 AM
stapel
sin^2(x) = 1 - cos^2(x) = [1 - cos(x)][1 + cos(x)]

Then cancel....

Does that help? (Wink)