i'm having trouble with this limit. Can you guys help?

$\displaystyle \lim_{x\to 0} \frac{x(1-\cos(x))}{\sin^2 x} $

Also, i cant use L'Hopital's rule

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- Sep 13th 2009, 10:01 AMdiscobobTrig Limits
i'm having trouble with this limit. Can you guys help?

$\displaystyle \lim_{x\to 0} \frac{x(1-\cos(x))}{\sin^2 x} $

Also, i cant use L'Hopital's rule - Sep 13th 2009, 10:14 AMstapel
sin^2(x) = 1 - cos^2(x) = [1 - cos(x)][1 + cos(x)]

Then cancel....

Does that help? (Wink)