If u = 1 + x, then you have x = u - 1, ln(1 + x) = ln(u), and du = dx....
According to the directions, I should be using u-substitution and integration by parts to find the indefinite integral of:
x ln(1 + x) dx
This is the only problem that I am having an immense amount of trouble with. It seems useless to use any u-substitution (at least at this point). I tried to use integration by parts with u = ln(1 + x) and dv = x dx, but that gave me an integral of (x^2)/(1 + x) which I cannot seem to make go anywhere from that. Am I approaching this problem the wrong way?