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Math Help - Help deriving this function

  1. #1
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    Help deriving this function

    I need to find the stationary point, but I'm unsure the partial derivatives.

    f(x)=e^{-x^2-y^2}

    Any help will be appreciated
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  2. #2
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     f(x)=e^{-x^2-y^2}

    With respect to x hold y constant and vice versa. Consider when y= e^{f(x)} \Rightarrow \frac{dy}{dx}= f'(x)e^{f(x)}

    so

     \frac{\partial f}{\partial x} = -2xe^{-x^2-y^2}<br />

    can you find

     \frac{\partial f}{\partial y} ?
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  3. #3
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    It might be simpler to write e^{-x^2-y^2} as e^{-x^2}e^{-y^2}. What is the derivative of Ce^{-x^2} with respect to x?
    Last edited by mr fantastic; September 13th 2009 at 04:13 AM.
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