Hello,

Ive been having trouble solving this problem.

I could really use help :)

In this case find y in terms of x

dy/dx= (√x+5)^2

Thank you in advance

Rob

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- Sep 13th 2009, 12:52 AMOasis1993Find y in terms of x
Hello,

Ive been having trouble solving this problem.

I could really use help :)

In this case find y in terms of x

dy/dx= (√x+5)^2

Thank you in advance

Rob - Sep 13th 2009, 01:54 AMpickslides
$\displaystyle \frac{dy}{dx}= (\sqrt{x}+5)^2$

$\displaystyle y= \int(\sqrt{x}+5)^2~dx$

I suggest expanding the brackets and integrating each term individually.

$\displaystyle y= \int x+10\sqrt{x}+25~dx$

Can you take it from here? - Sep 13th 2009, 02:39 AMOasis1993
- Sep 13th 2009, 02:50 AMpickslides
$\displaystyle y= \int x+10\sqrt{x}+25~dx$

$\displaystyle y= \int x~dx+\int 10\sqrt{x}~dx+\int 25~dx$

Now use the following rule for each part.

$\displaystyle \int x^n~dx = \frac{x^{n+1}}{n+1}+c$

for each part.

__Spoiler__: - Sep 13th 2009, 04:32 AMmr fantastic