Is e a constant?
$\displaystyle D_x (e) = e^1(D_x 1) $
Derivative of e ---> will it equal to zero?
THanks
The derivative of $\displaystyle y=e$ is $\displaystyle y'=0$.
Since it is a constant function its derivative is zero.
Ah!
But what is the derivative of $\displaystyle y=\sqrt{e}$.
I am just saying that, is because I once was teaching my classmates Calculus. Just the moment I explain the derivative of 'e' is zero and give them this problem they start doing this.