Consider the sequence of real numbers defined by: , , Prove that:
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My attempt
Hello again, try to show that
Originally Posted by MPK Hello again, try to show that Why is
try to prove it
Originally Posted by MPK try to prove it not is ?
No x) there are many products above and under you have 1*3*5*7***(2n-1)*(2n+1) and etc
Originally Posted by MPK No x) there are many products above and under you have 1*3*5*7***(2n-1)*(2n+1) and etc Oh yes. But I do not understand how you found
try to figure out, you didn't take time
Originally Posted by MPK try to figure out, you didn't take time I think: The numerator => multiplication between the odd numbers The denominator => multiplication between the numbers pairs
yes it is the idea but you have to calculate more to get a good result, hint : show that (2n)! = n! * 2^n
Originally Posted by MPK yes it is the idea but you have to calculate more to get a good result, hint : show that (2n)! = n! * 2^n OK. In this equation if I use I have
I find:
for n = 2 i have 1/122880
Originally Posted by MPK for n = 2 i have 1/122880 Problem: 1) Prove that How can I multiply factorial ?
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