The edge of the floor of the regular triangular prism is a. The slant side gamma one side of which is against the floor edge a and the other side which crosses the point M, forms the angle alfa. The point M divides the edge of the side as 3:5, beginning from the bottom floor. Declare and calculate the area of the slant gamma and the relation of the parts of the prism.
alfa = 30 degrees
a = 10 cm
October 10th 2005, 08:16 AM
You realize 'alpha' and 'a' are nowhere to be found in your diagram. When I see a diagram where I need to guess what is what I would rather skip it.
Anyway the solution requires a bt more information. Is it an isosceles triangle? we only know one side of the triangle so I don't think there is enough info.