"Given y=2sin2t and x=5cos4t, determine dy/dx." I know I have to use the chain rule here by: dy/dx = dy/dt x dt/dx but I'm not sure how to isolate dy/dt and dt/dx. Please help.
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Originally Posted by Melnarie "Given y=2sin2t and x=5cos4t, determine dy/dx." I know I have to use the chain rule here by: dy/dx = dy/dt x dt/dx but I'm not sure how to isolate dy/dt and dt/dx. Please help. There's a slightly easier way. ==> ==> Thus -Dan
oooh! thanks so much!!
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